A fair coin can be used to simulate probabilities 1/4, 27/64, etc. Find p that simulates 1/2 & 1/3. #FigureThat #math #probabilitypic.twitter.com/2pWiPShO47
The short answer is I don't know. I will review the other answers submitted. All I can muster is using permutations of the Tails/Heads order
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p=1/6 doesn't work. Denom is 6^n (1 mod 5). So numer is 3 mod 5 to get prob 1/2. All outcomes have numer 0 mod 5 except one which is 1 mod 5
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Thanks. The logic is that to get 1/2 and 1/3 you will need some coin that is 1/p where (1/p)^m*(p-1)/p^n = 1/2 and 1/3?
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