A second probability problem #FigureThat #math #probabilitypic.twitter.com/S6Q7Uwddsu
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1) Condition on boxes 1,5,6. Question now is if 2,3,4 are ordered, which has prob 1/6. 2) Condition on 1,6. Ineq are independent, so 1/2*1/2
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For instance consider the case [1,_,_,_,5,6], then you have to distribute 2,3,4 into the blanks: there are 6 possibilities and only 1 valid
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If we take for example [4,_,_,_,1,3] instead, you have to distribute 2,5,6 into the blanks, but the probability is again 1/6.
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