Does that mean "(define x 0)" is a universal algorithm capable of simulating any Turing Machine?
-
-
-
Over long enough timescales.
End of conversation
New conversation -
-
-
Therefore deterministic algorithms are unrunnable.
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.