A geometric proof that for 0<r<1, (1-r) + (1-r)r + (1-r)r² + ... = 1, and therefore that 1 + r + r² + ... = 1/(1 - r)pic.twitter.com/r22dM7PoUM
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Please, I'd be very interested to see it
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Oh wow, okay! I need to think about this. Thank you
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Lemme know if you need more hints. It's probably a good idea to start with the r = 1/n case, and then work your way gradually up to r = m/n. The r = 1/3 case is similar enough to the r = 1/2 case to be fairly straightforward, given the foregoing picture.
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Reminds me of cellular automata
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