Euler observed that n^2-n+41 is prime for n=0,1,2,...,40.
Replying to @divbyzero
Euler also asked, and answered, the related question: for which m is n^2 - n + m prime for all n = 0, 1, 2, ... , m-1? Which naturally led him to conjecture (correctly) that m = 41 is the largest such m,
9:27 AM - 3 Oct 2018
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