A direct equation for adjusting d for measurement error. Can be made by rearranging the three above. @dingding_peng
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Replying to @KirkegaardEmil
so you want to plug in d, n1, n2, reliabilities and get corrected d?
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Replying to @dingding_peng @KirkegaardEmil
I mean you could do that but it would only look more messy and not add any information, would it?
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Replying to @dingding_peng @KirkegaardEmil
2*((d/sqrt(d^2 + ((n1 + n2)^2/(n1*n2))))/sqrt(rl1 * rl2)))/sqrt(1-((d/sqrt(d^2 + ((n1 + n2)^2/(n1*n2))))/sqrt(rl1 * rl2))^2
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Replying to @dingding_peng @KirkegaardEmil
with rl1 and rl2 being the reliabilities. but if I was doing that in my code, I'd prefer multiple lines, way more readable
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Replying to @dingding_peng
Yes, just wondering if there was a neat equation for presentation purposes.
@dingding_pengpic.twitter.com/UOX0ghZlfQ
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Replying to @KirkegaardEmil
aaaah, okay! Now I see. I actually think that the multiple line solution is neater, don't think you can simplify much
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Replying to @dingding_peng
Oh well. I'm not particularly good with algebra, so I'm not the right person ti ask to rearrange stuff without errors! :)
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Replying to @KirkegaardEmil
If you're good, maybe you can solve this one! :) http://emilkirkegaard.dk/en/?p=6570 It's something with infinite series that converge
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Replying to @KirkegaardEmil
I tend to solve everything using WolframAlpha, not sure whether that qualifies as a skill...
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Don't think WA works for this one. Basically have to show (5) from (1-4). Empirically, it works out (when n = large). @dingding_pengpic.twitter.com/MyBHZrrEfU
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