Make a formula to correct d for measurement error directly. Just a substitution job. @bechhof
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Thanks. Twitter will use this to make your timeline better. UndoUndo
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That would help. Right now I'm having a hard time even seeing what you did. :P
@bechhof@dingding_peng -
Beyond my abilities, but seems that I wasn't just lucky with my empirical math. :)
@bechhof@dingding_peng
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still not sure what you want? Get d (corrected for rel.?) from the other stuff? If you don't care what's on right side>
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it's just a long chain of the parts you already got? Or do you also want it simplified and with d popping up again?
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A direct equation for adjusting d for measurement error. Can be made by rearranging the three above.
@dingding_peng -
so you want to plug in d, n1, n2, reliabilities and get corrected d?
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I mean you could do that but it would only look more messy and not add any information, would it?
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2*((d/sqrt(d^2 + ((n1 + n2)^2/(n1*n2))))/sqrt(rl1 * rl2)))/sqrt(1-((d/sqrt(d^2 + ((n1 + n2)^2/(n1*n2))))/sqrt(rl1 * rl2))^2
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with rl1 and rl2 being the reliabilities. but if I was doing that in my code, I'd prefer multiple lines, way more readable
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Yes, just wondering if there was a neat equation for presentation purposes.
@dingding_pengpic.twitter.com/UOX0ghZlfQ
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is it that d of the 1st equation? (probably noob question)
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Don't understand the question.
@joaoeira
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