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KevinSimler's profile
Kevin Simler
Kevin Simler
Kevin Simler
@KevinSimler

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Kevin Simler

@KevinSimler

Writer, software person, armchair anthropologist, dilettante. All genders, all political opinions welcome. Book: https://amzn.com/0190495995/ 

San Francisco, CA
meltingasphalt.com
Joined March 2011

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    1. Kevin Simler‏ @KevinSimler 14 Nov 2018
      • Report Tweet

      Quiz: It’s noon on the spring equinox and you’re standing at the equator; the sun is directly overhead. Suppose that light takes exactly 8 minutes to travel the distance between us and the sun. Where would you have to point a laser in order to hit the sun dead-center?

      4 replies 0 retweets 15 likes
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    2. Kevin Simler‏ @KevinSimler 14 Nov 2018
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      ^^^ a little physics/geometry puzzle I made up as a teenager I suggest trying to answer yourself before checking the replies for spoilers.

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    3. Kevin Simler‏ @KevinSimler 15 Nov 2018
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      The answer (near as I can reason): If we model the sun as stationary and the earth as doing all the movement, then to hit the sun, you just have to aim directly at it. The fact that the sun appears to move in the sky as light takes time to travel is a red herring.

      3 replies 0 retweets 10 likes
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    4. Roy Haddad‏ @royhaddad 15 Nov 2018
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      Replying to @KevinSimler

      I was thinking the only error should be from Earth's orbital velocity. Avg. appears to be 30 km/s, which the light would inherit, throwing it off by ~14,400 km by the time it gets to the Sun (only 1% of its diameter).

      2 replies 0 retweets 2 likes
    5. Kevin Simler‏ @KevinSimler 15 Nov 2018
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      Replying to @royhaddad

      Thanks! This is something I’ve always wondered about, and am still confused by. Can you explain with a few more words?

      1 reply 0 retweets 0 likes
    6. Adam Smith‏ @LaissezWhere 15 Nov 2018
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      Replying to @KevinSimler @royhaddad

      I'll take a shot at this. Whenever you trigger the laser, it's velocity can be decomposed into a vector of [very nearly c towards the sun, ~14km/s (sic) perpendicular to that]. The magnitude of that vector will be a speed of c, by relativity.

      1 reply 0 retweets 1 like
    7. Adam Smith‏ @LaissezWhere 15 Nov 2018
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      Replying to @LaissezWhere @KevinSimler @royhaddad

      30km/s*. And that's perpendicular to your aim because the Earth's velocity is tangential to the orbit, therefore perpendicular to the orbit's radius (your aim). Within the error factor of Earth orbit's ovalness.

      2 replies 0 retweets 1 like
    8. Adam Smith‏ @LaissezWhere 15 Nov 2018
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      Replying to @LaissezWhere @KevinSimler @royhaddad

      (I didn't check any of these numbers, but the explanation should hold.) I have no idea if relativity would meaningfully effect the result. Modeling light as Newtonian is a dangerous game. Solving the angle to actually hit dead center is some trig, or linear algebra?

      2 replies 0 retweets 1 like
      Kevin Simler‏ @KevinSimler 15 Nov 2018
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      Replying to @LaissezWhere @royhaddad

      Thanks, now I understand. You’re just modeling light as a very fast Newtonian particle which inherits the (almost negligible) lateral velocity of Earth. (I needed it spelled out as “Newtonian” to avoid getting confused by my hazy understanding of relativity.)

      9:37 PM - 15 Nov 2018
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        1. Roy Haddad‏ @royhaddad 16 Nov 2018
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          Replying to @KevinSimler @LaissezWhere

          Yes, Adam has my thinking right. I figured the Newtonian model should work here because light carries momentum and it’s always conserved

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