Quiz: It’s noon on the spring equinox and you’re standing at the equator; the sun is directly overhead. Suppose that light takes exactly 8 minutes to travel the distance between us and the sun. Where would you have to point a laser in order to hit the sun dead-center?
Thanks! This is something I’ve always wondered about, and am still confused by. Can you explain with a few more words?
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I'll take a shot at this. Whenever you trigger the laser, it's velocity can be decomposed into a vector of [very nearly c towards the sun, ~14km/s (sic) perpendicular to that]. The magnitude of that vector will be a speed of c, by relativity.
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30km/s*. And that's perpendicular to your aim because the Earth's velocity is tangential to the orbit, therefore perpendicular to the orbit's radius (your aim). Within the error factor of Earth orbit's ovalness.
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