I guess actually all time zones become adjacent at the poles. (Excluding +13, +14, and fractional zones.) Whatever. That doesn't count.
@Sniffnoy You could say X, Y are adjacent iff ∃z∈(X∪Y) such that every open set containing z intersects both X and Y.
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@InstanceOfClass That's the same as "cl(X) overlaps Y or cl(Y) overlaps X". It only uses topology. I'm confused about the motivation here. -
@Sniffnoy It avoids making all time zones adjacent. - 9 more replies
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