I actually think it is a kinda of a priori reason in a way because I think this really is implicitly defining what we mean by "force".
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Replying to @RyanDavidReece @rayohauno
hmm i think i disagree with you on this one about this being a purely mathematical statement.
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Replying to @InertialObservr @rayohauno
It is a consequence of the convention F = - dU/dx. That minus sign is what caries through to make the minus sign in L = T-U.
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Replying to @RyanDavidReece @rayohauno
right but the *relative* minus sign, no matter where it goes, is physical. That's the empirical fact i'm talking about. The fact that nature wants to "go downhill", as it were.
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Replying to @InertialObservr @rayohauno
That is our convention of what "down" means.
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Replying to @RyanDavidReece @rayohauno
yes, but it's the fact that nature chooses one thing over the other no matter what we call it, mathematically represented as a minus sign
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i.e. define "down" as the thing nature chooses , call it plus or minus or what you want it doesn't matter. But we need to distinguish between them somehow mathematically. But this i argue is physical content.
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Replying to @InertialObservr @rayohauno
F = ± dU/dx would cause L = T ± U. Is convention and math. What forces are needed to explain any given observation is physics.
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Replying to @RyanDavidReece @rayohauno
fair point , i do recall that you can derive this minus sign from the classical limit of relativity and it's essentially just the metric signature/2.. however i could also recall there being something else to worry about, that i can't recall at the moment
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right i wasn't saying fundamental, i was saying that it's empirical .. but i think if we take m<0 instead then everything works out
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