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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Hydrogen atom cross-sections •The probability distribution |Ψ|² of the electron's location is represented as a thermal map (Atom is in the (5,4,2) state)pic.twitter.com/qZDzwUR7gc

      19 replies 239 retweets 1,134 likes
    2. Dennis Wingo‏ @wingod Jan 28
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      Replying to @InertialObservr @revprez

      Those are gaussian distributions regarding location probability?

      1 reply 0 retweets 1 like
    3. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @wingod @revprez

      not necessarily gaussian, no. The probability density is a function of (r,θ,φ)

      1 reply 0 retweets 2 likes
    4. Dennis Wingo‏ @wingod Jan 28
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      Replying to @InertialObservr @revprez

      That's the coordinate system, not the location probability?

      1 reply 0 retweets 1 like
    5. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @wingod @revprez

      to talk about location you need to specify an origin .. eg. to talk about gaussian's you need to say Gaussian 'about what'

      3 replies 0 retweets 1 like
    6. Dennis Wingo‏ @wingod Jan 28
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      Replying to @InertialObservr @revprez

      Looks more Lorentzian in cross section.

      1 reply 0 retweets 1 like
    7. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @wingod @revprez

      it's just constant slices perp to the y axis. the angle just makes it look a bit funny

      1 reply 0 retweets 1 like
    8. Dennis Wingo‏ @wingod Jan 28
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      Replying to @InertialObservr @revprez

      Interesting, do the energy eigenstates have any temperature dependency?

      1 reply 0 retweets 1 like
      〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @wingod @revprez

      no, by definition.. the wave function can recieve temperature corrections but that's not going on here

      5:05 PM - 28 Jan 2020
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      • Rev Prez
      1 reply 0 retweets 1 like
        1. Dennis Wingo‏ @wingod Jan 28
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          Replying to @InertialObservr @revprez

          Ok, makes sense. I noticed that there was no temperature term.

          0 replies 0 retweets 1 like
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