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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @freddy_x @wood_croft

      because energy eigenstates have trivial time evolution .. if you prepare the state in some Ψnlm , then you are simply just more likely to find it in certain places than another, that's like the whole thing .. and you don't even need very exotic states to acheive this at all

      1 reply 0 retweets 2 likes
    2. Fred Joke‏ @freddy_x Jan 28
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      Replying to @InertialObservr @wood_croft

      The overwhelming majority of the hydrogen atoms in the universe have not been prepared and are spherically symmetric. No?

      1 reply 0 retweets 1 like
    3. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @freddy_x @wood_croft

      i don't see how that's relevant

      1 reply 0 retweets 1 like
    4. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @InertialObservr @freddy_x @wood_croft

      that's just the statement that the ground state is spherically symmetric

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    5. Wood Croft‏ @wood_croft Jan 28
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      Replying to @InertialObservr @freddy_x

      The other energy states are spherically symmetric too.

      1 reply 0 retweets 0 likes
    6. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @wood_croft @freddy_x

      No, only the (n,0,0) states.

      1 reply 0 retweets 3 likes
    7. яша‏ @trogggg Jan 28
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      Replying to @InertialObservr @wood_croft @freddy_x

      but if you dont know “what axis” the azimuthal angle is measured from your 2p orbital would be in a mixed state which is spherically symmetric, youd need a state preparation or external field which picks the basis for the l=1 harmonics to be in a pure state?

      1 reply 0 retweets 0 likes
    8. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @trogggg @wood_croft @freddy_x

      it has nothing to do with knowing .. the conversation is about pure states and quantum uncertainty , not classical uncertainty .. we say we prepare the atom in a particular state (n,l,m) .. is it spherically symmetric

      1 reply 0 retweets 0 likes
    9. яша‏ @trogggg Jan 28
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      Replying to @InertialObservr @wood_croft @freddy_x

      sure if THATS your question then its clearly not, but i think all the confusion in this branch of the thread was about real world examples and how classical uncertainty may apply when youre not preparing a specific (n,l,m) state, and then diff questions were getting conflated

      2 replies 0 retweets 2 likes
    10. Fred Joke‏ @freddy_x Jan 28
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      Replying to @trogggg @InertialObservr @wood_croft

      The initial question was how to represent an hydrogen atom. Drawing some orbitals gives a poor representation of an hydrogen atom in my opinion.

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr Jan 28
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      Replying to @freddy_x @trogggg @wood_croft

      okay that's fine, but that's a different point and clearly different upon reading the thread, than what wood was arguing

      3:08 PM - 28 Jan 2020
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