i think it's time to re-indoctrinate the youthpic.twitter.com/tdi0bFAYOA
Show this thread
-
The actual wavefunction is a linear combination of the eigenfunctions where the angular dependence goes away. This is intuitive. The atom normally doesn't have the notion of angle.
what do you mean "actual"? Hydrogen can certainly be in an energy eigenstate .. the energy quantum number doesn't depend on azimuthal quantum numbers, but the angular momentum observables do
-
-
Take the 2p orbital, for example. The electron is in a superposition of 2px, 2py and 2pz. |ψ2p> = (|2px>+|2py>+|2pz>)/sqrt(3). Now take the pdf <ψ2p|ψ2p> and you'll see the dependence on the angles cancels out. It only depends on the distance to the nucleus.
-
That's just not true.. a superposition of the 2ps is a superposition of 3 dumbbells each of which has an angular dependence in an independent direction .. it *can* happen that you measure l=0, but it can also happen that you measure l=1
- 13 more replies
New conversation -
-
-
azimuthal and polar*
-
I think this may have been the source of confusion all along? A wavefunction in the |n,l,m> basis should not have *azimuthal* dependence (polar is OK), yet yours has both. So it has to be a superposition (I think it’s |7,6,4> + |7,6,-4>).
- 2 more replies
New conversation -
-
-
I just googled "energy eigenstate" and I understood it LESS if that was even possible. "a quantum state with all observables independent of time."? No wonder I rage quit my degree.
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.