I know you know what you’re talking about, I just disagree with you on this point
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Replying to @InertialObservr
Just out of curiosity. The probability that we talk about in QM, do you think of it as a Bayesian ir as frequentists?
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Replying to @Draquarkula
I haven’t thought about it very deeply, Since I thing being an everettian is the way to go
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Replying to @InertialObservr
I might be wrong, but I think thats the key point of our disagreement. Repeting experiments so that we can reconstruct known asymptotic stated may be inherently frequentists. While imagining paths from the particles point of view sounds very Bayesian to me.
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Replying to @Draquarkula
Well I’m not sure about that, I try to keep my statements about QM independent of interpretation If I had to refine I would say: ‘there is no meaningful way to say a fundamental particle is in the state (x,p).’ Implying that it does not follow any trajectory
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Replying to @InertialObservr
I am sure that you're familiar with the positive electron. Looking at fig1 of the Discovery paper I may be biased but that looks a while lot like a trajectory. And they understood their own magnets so well that they even measured the momentum of itpic.twitter.com/PSiWNHaPcs
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You (and the cloud chamber, the room, the planet, etc.) get entangled with the particle. Once it interacts with the particles in the cloud chamber, it entangles with them (and you), which localizes the particle in some location given some environmental eigenstate.
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This means there is an extremely high probability (basically P=1) that you will continue finding it close by in the next moment.
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Replying to @Vampyricon @InertialObservr
If that was the case the particle wouldnt be able to move. Thats basically the Quantum Zeno effect.
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No, i t wouldn't be able to evolve purely in time under the *same* schrodinger equation.. the constant measurement is actually the very things that is causing the quantum decoherence!
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