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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. Daniel Navarro‏ @Draquarkula Jan 24
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      Replying to @InertialObservr

      I disagree with the first bullet point. If there was no such a thing, how could we even prove the second point? What I mean is that one has to measure both the position and momentum of a particle many times if one aspires to fill a histogram that may resamble a PDF.

      3 replies 0 retweets 3 likes
    2. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @Draquarkula

      If you confine a particle to go through a tiny slit, the more spread you will have in the momentum distribution. Take a photon, as it goes through the slit you will precisely where it is but you won't know the direction it is headed (i.e. it's instantaneous momentum vector)

      1 reply 0 retweets 15 likes
    3. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @InertialObservr @Draquarkula

      Make the slit smaller and smaller, the light the resulting interference pattern will grow wider and wider. If you can get both at the same time then you my friend will get a nobel prize

      1 reply 0 retweets 14 likes
    4. Daniel Navarro‏ @Draquarkula Jan 24
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      Replying to @InertialObservr

      Again, look at how you would measure the interference pattern. I think that one would throw one photon at a time. And for each photon, one would need to know both the slit size and the place where it lands. Effectively measuring both x and p.

      2 replies 0 retweets 3 likes
    5. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @Draquarkula

      No, quantum particles don’t follow definite trajectories.. this is the whole point of the path integral approach. It envisions space as infinitely many infinitesimally small slits stacked one after another.

      2 replies 0 retweets 17 likes
    6. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @InertialObservr @Draquarkula

      You can’t say it left the slot with this or that momentum and followed some definite trajectory and work backwards

      1 reply 0 retweets 7 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @InertialObservr @Draquarkula

      We can say this only of asymptotic non interacting states, which we do in the LHC

      1 reply 0 retweets 6 likes
    8. Daniel Navarro‏ @Draquarkula Jan 24
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      Replying to @InertialObservr

      In essence I am not arguing against Heissenbergs principle. I am arguing against applying it to a single event, when it is an expression on ensambles/many events.

      1 reply 0 retweets 2 likes
    9. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @Draquarkula

      But you were just applying the photon scattering to a single event saying you could work backwards and find the momentum

      2 replies 0 retweets 6 likes
    10. Daniel Navarro‏ @Draquarkula Jan 24
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      Replying to @InertialObservr

      Read back carefully. I mentioned position and momentum before you called the slit experiment. After that, I only wrote about x and p as conjugates of each other I know this was misleading on my part, but you were the one who wrote about trajectories and momentum reconstruction

      1 reply 0 retweets 1 like
      〈 Berger | Dillon 〉‏ @InertialObservr Jan 24
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      Replying to @Draquarkula

      How could you then possibly reconstruct the initial momentum, as you claimed you could ‘effectively’ do?

      8:53 PM - 24 Jan 2020
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        1. Daniel Navarro‏ @Draquarkula Jan 24
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          Replying to @InertialObservr

          In the slit case. You measure the slit size and the location where the photon arrives. The conjugates may be the size of the slit and the width of the distribution of the endpoint of the photons. To prove such a conjugate relation, one has to measure both several times.

          0 replies 0 retweets 0 likes
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        1. Daniel Navarro‏ @Draquarkula Jan 24
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          Replying to @InertialObservr

          In other words, the slit experiment is not about position vs momentum. It is about comparing widths after making many measurements

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