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The Heisenberg Uncertainty Principle
(Δx Δp ≳ ℏ)
• Implies that there really is no such thing as 'a particle is at 𝑥 with momentum 𝑝'
• That is, the more narrow the 𝑥-PDF |Ψ(x)|², the more broad the 𝑝-PDF |Φ(p)|² will become & vice versa (
)pic.twitter.com/6AUqy3Mpt1
I made this animation by directly following the rules of Quantum Mechanics •For a given state Ψ(x), the probability amplitude for momentum Φ(p) is the Fourier Transform of Ψ(x) The animation is made by varying the parameter (a) Note that: Lim(Ψ, a→0) = δ(x)pic.twitter.com/kP2b8AHeBD
Why is the normalization factor 1/sqrt(a(sqrt(π)) rather than simply 1/sqrt(aπ)? 
is that a typo or am I missing something?
because you gotta square the amplitude
I've always been confuses by that Dirac. If the wave becomes a Dirac, does the square amplitude toi ? The square if a Dirac being undefined
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