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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. John Carlos Baez‏ @johncarlosbaez Jan 11
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      John Carlos Baez Retweeted Simon Tardivel

      A beautiful solution of the gravitational 4-body problem. But keep watching, because it's not stable!https://twitter.com/simon_tardivel/status/1215728659010670594 …

      John Carlos Baez added,

      0:16
      Simon Tardivel @simon_tardivel
      Par exemple, prenons une jolie configuration à... 4 corps désormais ! Regardez les premiers tours, c'est joli hein... Ouais continuez à regarder... #SpoilerAlert CA VA MAL FINIR ! pic.twitter.com/rxQeBkJ2kr
      Show this thread
      48 replies 1,005 retweets 4,196 likes
      Show this thread
    2. Josh Foster‏ @JoshuaDFoster1 Jan 11
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      Replying to @johncarlosbaez @InertialObservr

      I don't understand why it's unstable. I'm the farthest thing from a physicist, so I'm sure I'm missing something obviously, but it seems to me like it should be stable. Is something influencing their movement besides each other?

      3 replies 0 retweets 3 likes
    3. John Carlos Baez‏ @johncarlosbaez Jan 11
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      Replying to @JoshuaDFoster1 @InertialObservr

      Lots of systems are unstable, and then they can *look* like they're doing something simple, but in reality they're not quite, and the deviation from simple behavior gradually builds up over time and suddenly spirals out of control. Just solve the equations...

      3 replies 0 retweets 33 likes
    4. Gary Fredericks‏ @gfredericks_ Jan 11
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      Replying to @johncarlosbaez @JoshuaDFoster1 @InertialObservr

      this one is static under perfect conditions, right? perfect symmetry, no perturbations, etc.? the fact that it starts out symmetric at least tells me it can't end the way it does in the animation

      1 reply 0 retweets 4 likes
    5. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 11
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      Replying to @gfredericks_ @johncarlosbaez @JoshuaDFoster1

      That’s the thing it’s *not* perfectly symmetric, it just looks that way to our monkey brains. There is a ever so slight difference in initial conditions that breaks the symmetry

      3 replies 0 retweets 12 likes
    6. Chris Robbins‏ @Grallator Jan 13
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      Replying to @InertialObservr @gfredericks_ and

      It may be symmetric, but if solved with a numerical scheme there will be truncation and representation errors plus the scheme will have finite order accuracy. These will introduce small perturbations which will be amplified in a mathematically unstable system.

      1 reply 0 retweets 4 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 13
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      Replying to @Grallator @gfredericks_ and

      Yes but I’m assuming OP accounted for that

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr Jan 13
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      Replying to @InertialObservr @Grallator and

      But even if not, it’s still not symmetric just for a different reason

      10:48 AM - 13 Jan 2020
      2 replies 0 retweets 0 likes
        1. Смерть Пиндосам!‏ @alkhwarizmi42 Jan 13
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          Replying to @InertialObservr @Grallator and

          Смерть Пиндосам! Retweeted Simon Tardivel

          It seems symmetric to me. Also, the divergence comes the solver.https://twitter.com/simon_tardivel/status/1216056485123366913 …

          Смерть Пиндосам! added,

          Simon Tardivel @simon_tardivel
          Replying to @simon_tardivel @davidsaidthis
          Here, the "reason" it diverged is indeed that the integrator was not perfect and errors built up over time. But the errors did not make the system unstable, they just gave it a liiiiittle nudge. Then the natural dynamics did the job!
          0 replies 0 retweets 0 likes
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        1. Chris Robbins‏ @Grallator Jan 13
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          Replying to @InertialObservr @gfredericks_ and

          Chris Robbins Retweeted Vicky

          It’s pretty hard to account for numerical solver differences (see https://twitter.com/graymalk/status/1189523925983776768?s=21 …). The asymmetry is (probably) numerical so an artefact of the computing rather than the physics. However the mathematics shows the system is unstable to perturbation hence the divergence.https://twitter.com/graymalk/status/1189523925983776768 …

          Chris Robbins added,

          Vicky @graymalk
          It's always so much fun to do math on computers. 🤣 Machine 1: 1.1682064664487028e-17 Machine 2, same code: -5.84103233224e-18 Machine 3, same code: -3.26732746085e-17 This is an example that uses very small numbers but I've seen it with bigger numbers.
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