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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. Anomaly Canceller‏ @litgenstein Jan 3
      • Report Tweet
      • Report NetzDG Violation

      Physicists had the chance to name the supersymmetric partner (which are hypothesized to avoid fine tuning) of the quark a “superquark” and instead opted for...squark:pic.twitter.com/HOTJR0TEUm

      16 replies 13 retweets 122 likes
      Show this thread
    2. This Tweet is unavailable.
    3. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 3
      • Report Tweet
      • Report NetzDG Violation
      Replying to @LambdaQG @litgenstein

      you don't need string theory to talk about supersymmetry

      1 reply 0 retweets 5 likes
    4. Bryan Laughland‏ @weta2009nz Jan 3
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      Replying to @InertialObservr @LambdaQG @litgenstein

      Correct

      1 reply 0 retweets 2 likes
    5. This Tweet is unavailable.
    6. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 3
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      Replying to @LambdaQG @weta2009nz @litgenstein

      supersymmetry is a symmetry that exchanges bosons <--> fermions .. you don't need string theory for this you just need the lagrangian to be invariant under this exchange. The simplest model is the Wess-Zumino model

      2 replies 0 retweets 6 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 3
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      Replying to @InertialObservr @LambdaQG and

      of course you first need to define what a supersymemtric transformation even looks like. it's actually a continuous symmetry generated by the SUSY graded lie-algebras and not just a discrete symmetry

      1 reply 0 retweets 3 likes
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      〈 Berger | Dillon 〉‏ @InertialObservr Jan 3
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      Replying to @LambdaQG @weta2009nz @litgenstein

      that's if you gauge SUSY

      5:29 PM - 3 Jan 2020
      • 1 Like
      • Qasim
      1 reply 0 retweets 1 like
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        1. 〈 Berger | Dillon 〉‏ @InertialObservr Jan 3
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          Replying to @InertialObservr @LambdaQG and

          but you can only gauge if the group was continuous to begin with

          1 reply 0 retweets 1 like
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