hmm what do you mean? this is the singlet representation, an irreducible representation, of su(2) x su(2)
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Replying to @InertialObservr
I mean the following: given a system with Hilbert state X and another with Y, the joint state space is X⨂Y. A state there X & Y are independent would look like a⨂b (a decomposable tensor) for some a∊X and b∊Y, but not all elements of X⨂Y are decomposable.
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Replying to @lisyarus @InertialObservr
In general, elements of X⨂Y are linear combinations of decomposable tensors, just like in your post.
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Replying to @lisyarus
I’m seeing what you’re saying, but I thought that a tensor product of reps can always be decomposed into a direct sum of its irreps.. or is that just SU(N)?
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Replying to @InertialObservr
You are right, but I'm not talking about irreps of SU(N) or spins or anything in particular, just quantum systems in general.
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Replying to @lisyarus
I think I see .. but doesn’t this example (main tweet) show that this is not always true of entangled states ?
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Replying to @InertialObservr
Sorry, what "this" is not always true of entangled states? I think I lost the point :(
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Replying to @lisyarus
I see I just thought you were stating a necessary and sufficient condition
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Replying to @InertialObservr @lisyarus
“this” being your realization about decomposable tensors
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Replying to @InertialObservr
No, I mean just the idea. For a decomposable tensor measurements of X and Y systems are independent, but for a general (entangled) one those become dependent.
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