Quick Introduction To Quantum Entanglementpic.twitter.com/9aDo9lAuNC
You can add location information to your Tweets, such as your city or precise location, from the web and via third-party applications. You always have the option to delete your Tweet location history. Learn more
I’m seeing what you’re saying, but I thought that a tensor product of reps can always be decomposed into a direct sum of its irreps.. or is that just SU(N)?
You are right, but I'm not talking about irreps of SU(N) or spins or anything in particular, just quantum systems in general.
I think I see .. but doesn’t this example (main tweet) show that this is not always true of entangled states ?
tensor product of irreps* I mean
Tensor product of any reps (or irreps) is still a representation, and for compact groups (e.g. SO(N), SU(N), Spin(N), finite groups) any representation decomposes into irreps. (technically I believe you need the reps to be strongly continuous, though)
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.