Does it make sense to say that the processes represented by Feynman diagrams and path integrals (like beta decay) are “real?” If you want to say in what sense they are or are not real, please respond!
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Replying to @litgenstein
Only asymptotic states (ie on-shell) are “real” ..
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Replying to @InertialObservr @litgenstein
But sometimes the momenta of the incoming asymptotic states are different from the momenta of the outgoing particles. Thus something must happen in-between which implies that, at least in some sense, interaction processes must be real too.
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Replying to @JakobSchwich @litgenstein
Which processes are you referring too? Conservation of momentum is one of the holiest of conservation laws! if there is kissing momentum that (I think) just means that some on shell particle (DM/neutrinos?) escaped without detection
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Replying to @InertialObservr @litgenstein
Ah no. I just meant that interactions do happen between particles. We can observe this because there are scattering processes p1p2->p3p4. We not only observe that two particles go in and two particles go out, but also that their momenta change. Hence interaction processes ∼ real
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Replying to @JakobSchwich @litgenstein
ahh I see what you’re saying.. and that’s a good point! The fact that the momentum distribution is what we would expect from an interacting QFT .. You’re right, but I more so think that the sum over all interactions (the blob) is the ‘real’ physical thing
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*something* certainly non classical happens “it is I know not what” -John Locke
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