What about 1/(distance)² ?
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right but i'm talking about the incident intensity, standing 10 yards away cupping my hands would lead to a higher incident intensity
my understanding was that the intensity of the laser depended on the dispersion angle Θ=2θ, which itself is dependent on distance traveled and source etcpic.twitter.com/p39saQkQbq
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right, all I'm clarifying is that if you average over the profile of the beam at a given far-field distance r, the average power/area still goes like 1/r^2
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