What about 1/(distance)² ?
right but i'm talking about the incident intensity, standing 10 yards away cupping my hands would lead to a higher incident intensity
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my understanding was that the intensity of the laser depended on the dispersion angle Θ=2θ, which itself is dependent on distance traveled and source etcpic.twitter.com/p39saQkQbq
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right, all I'm clarifying is that if you average over the profile of the beam at a given far-field distance r, the average power/area still goes like 1/r^2
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yeah, I guess I was confused by "so that the intensity drops off more slowly" I interpreted "drops off more slowly" to mean goes as O(1/r^k) for k<2, not just changing the constant of the intensity, but I guess that's the computer scientist in me being pedantic

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that's a fair point though .. i can see how that could be confusing
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