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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Absolutely Amazing Physicists (!) discover a new fundamental and amazing mathematical fact: You can get the Eigenvectors of a matrix using ONLY its Eigenvalues https://arxiv.org/pdf/1908.03795.pdf …pic.twitter.com/Mt797mmqDk

      74 replies 933 retweets 3,076 likes
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    2. TradeTherapAnalytics‏ @TradeTexasBig 13 Nov 2019
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      Replying to @InertialObservr

      What is new here ?

      1 reply 0 retweets 2 likes
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @TradeTexasBig

      ??? the fact that eigenvalues alone determine the eigenvectors!

      2 replies 1 retweet 21 likes
    4. TradeTherapAnalytics‏ @TradeTexasBig 13 Nov 2019
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      Replying to @InertialObservr

      I felt like i had seen it in strang either the svd or spectral form ..but maybe not . You can write eigen vectors using eigen values in clever ways , this looks eerily similar

      1 reply 0 retweets 3 likes
    5. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @TradeTexasBig

      no! .. of course you USE eigenvalues to find the eigenvectors, but the fact that they are completely determined by them is crazy

      3 replies 0 retweets 19 likes
    6. Scott A. Hill‏ @scottahill 13 Nov 2019
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      Replying to @InertialObservr @TradeTexasBig

      This can’t be true. For example, the Pauli matrices have identical eigenvalues, but different eigenvectors. I wonder how the paper deals with that.

      2 replies 0 retweets 0 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @scottahill @TradeTexasBig

      No, the eigenvectors of any one of the three pauli matrices span the entire 2x2 vector space.. so the eigenvectors of the other two are just a linear combination of the one we chose to diagonalize (usually σz)

      1 reply 0 retweets 1 like
    8. Scott A. Hill‏ @scottahill 13 Nov 2019
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      Replying to @InertialObservr @TradeTexasBig

      Of course, but if I tell you “I’ve got a 2x2 matrix with eigenvalues +1 and -1, give me the eigenvectors”, what would you respond with? (1,0) and (0,1)? (1,1) and (1,-1)?

      1 reply 0 retweets 1 like
      〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @scottahill @TradeTexasBig

      well you need the matrix! you can't just give me random numbers lol

      6:27 PM - 13 Nov 2019
      2 replies 0 retweets 0 likes
        1. Craig Nicholas‏ @ThePathological 13 Nov 2019
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          Replying to @InertialObservr @scottahill @TradeTexasBig

          Yes, this is the whole point. The eigenvectors are not completely determined by the eigenvalues, they depend on the matrix

          0 replies 0 retweets 5 likes
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        1. Scott A. Hill‏ @scottahill 13 Nov 2019
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          Replying to @InertialObservr @TradeTexasBig

          But if I have the matrix and the eigenvalues, then I already know how to find the eigenvectors! I think your excitement is coming from a deeper knowledge of linear algebra than I possess. :D

          0 replies 0 retweets 1 like
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