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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Absolutely Amazing Physicists (!) discover a new fundamental and amazing mathematical fact: You can get the Eigenvectors of a matrix using ONLY its Eigenvalues https://arxiv.org/pdf/1908.03795.pdf …pic.twitter.com/Mt797mmqDk

      74 replies 933 retweets 3,076 likes
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    2. TradeTherapAnalytics‏ @TradeTexasBig 13 Nov 2019
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      Replying to @InertialObservr

      What is new here ?

      1 reply 0 retweets 2 likes
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @TradeTexasBig

      ??? the fact that eigenvalues alone determine the eigenvectors!

      2 replies 1 retweet 21 likes
    4. TradeTherapAnalytics‏ @TradeTexasBig 13 Nov 2019
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      Replying to @InertialObservr

      I felt like i had seen it in strang either the svd or spectral form ..but maybe not . You can write eigen vectors using eigen values in clever ways , this looks eerily similar

      1 reply 0 retweets 3 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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      Replying to @TradeTexasBig

      no! .. of course you USE eigenvalues to find the eigenvectors, but the fact that they are completely determined by them is crazy

      6:12 PM - 13 Nov 2019
      • 19 Likes
      • Jonathan Dursi Isak Westerlund KKN danilo Sam Havens Val Anthony Balagon
      3 replies 0 retweets 19 likes
        1. New conversation
        2. Scott A. Hill‏ @scottahill 13 Nov 2019
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          Replying to @InertialObservr @TradeTexasBig

          This can’t be true. For example, the Pauli matrices have identical eigenvalues, but different eigenvectors. I wonder how the paper deals with that.

          2 replies 0 retweets 0 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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          Replying to @scottahill @TradeTexasBig

          No, the eigenvectors of any one of the three pauli matrices span the entire 2x2 vector space.. so the eigenvectors of the other two are just a linear combination of the one we chose to diagonalize (usually σz)

          1 reply 0 retweets 1 like
        4. 3 more replies
        1. New conversation
        2. TradeTherapAnalytics‏ @TradeTexasBig 13 Nov 2019
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          Replying to @InertialObservr

          I will wait for others to opine also . I know tao said what he said . I am not surprised by that form still

          1 reply 0 retweets 0 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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          Replying to @TradeTexasBig

          well you should be .. i don't know what to tell you

          0 replies 0 retweets 15 likes
        4. End of conversation
        1. New conversation
        2. Scott A. Hill‏ @scottahill 13 Nov 2019
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          Replying to @InertialObservr @TradeTexasBig

          The formula in the paper assumes you know the eigenvalues of various submatrices M of the matrix as well, or am I misreading it?

          1 reply 0 retweets 2 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 13 Nov 2019
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          Replying to @scottahill @TradeTexasBig

          You’re right! I was addressing comments of a similar concern .. I’ve updated the thread and addressed those. Thanks!

          0 replies 0 retweets 1 like
        4. End of conversation

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