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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 9 Nov 2019
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      (1) The Weak Force is extremely short ranged: its potential is *almost* Coulomb's Law (2), but exponentially suppressed due to the fact its force carriers W⁺⁻, Z⁰ are massive (i.e. m≠ 0) (3) The second term in the last equation (kr) is what makes the strong force so "strong"pic.twitter.com/5GMsNeUb83

      12 replies 95 retweets 420 likes
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    2. 〈 Berger | Dillon 〉‏ @InertialObservr 9 Nov 2019
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      How do we get the potentials of the 3-fundamental forces from first principles? Quantum Field Theory (1) Specifically, we take the Fourier Transform of the Feynman diagram that describes each force We can *almost* get all 3 this way. Everything except the Strong Force (2/N)pic.twitter.com/5ajfg9baf4

      9 replies 17 retweets 107 likes
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    3. 〈 Berger | Dillon 〉‏ @InertialObservr 9 Nov 2019
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      For the Gluons, we *do* obtain the "Coulomb" term (1/r) but we don't get the linear term (kr). To find out what’s going on, we’ll need a couple facts.pic.twitter.com/oJ1M69TCI4

      3 replies 6 retweets 44 likes
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    4. 〈 Berger | Dillon 〉‏ @InertialObservr 9 Nov 2019
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      Charge, mass etc *change* depending on the energy scale! •The Strong Force has the unique property that α ↘️ as E↗️ •There is an E where out denominator will become 0 and hence our series will diverge! This is called a "Landau Pole" and is exactly the source of our troublespic.twitter.com/FL9VnoL312

      3 replies 11 retweets 47 likes
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    5. 〈 Berger | Dillon 〉‏ @InertialObservr 9 Nov 2019
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      QCD becomes ill defined at: E≲100 GeV ⇔ distance ≳10⁻¹⁵m (found by solving previous eqn) So it's no surprise that the (kr) term isn't predicted by QCD, since we never even had a well-defined theory at the distance scales which this term would be relevant from the very startpic.twitter.com/l3GDG9oM2v

      5 replies 6 retweets 39 likes
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    6. Lewis Tunstall‏ @_lewtun 10 Nov 2019
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      Replying to @InertialObservr

      More generally, since QCD is asymptotically free (α -> 0 as E -> inf), it may be the only physical QFT we know of that is well-defined at ALL energy scales!

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 10 Nov 2019
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      Replying to @_lewtun

      1/4 true .. I strongly disagree with the statement that QCD is well defined at all scales .. namely, below the confinement scale ..

      1:52 AM - 10 Nov 2019
      2 replies 0 retweets 0 likes
        1. New conversation
        2. 〈 Berger | Dillon 〉‏ @InertialObservr 10 Nov 2019
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          Replying to @InertialObservr

          You can write an EFT.. but that’s a *different* lagrangian and hence different theory

          1 reply 0 retweets 0 likes
        3. Lewis Tunstall‏ @_lewtun 10 Nov 2019
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          Replying to @InertialObservr

          Correct, but I am not talking about EFTs. The d.o.f. in the lattice action are *quarks and gluons* - it is not a different theory.

          0 replies 0 retweets 0 likes
        4. End of conversation
        1. Lewis Tunstall‏ @_lewtun 10 Nov 2019
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          Replying to @InertialObservr

          Perhaps we are using “well-defined” to refer to different things. By “well-defined” I meant renormalizable - lattice QCD is an example of a theory that is renormalizable at all scales (including below the confinement scale). What do you mean by the term?

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