Electric Field of a point charge moving 90% the speed of light at its fastest point (All relativistic effects are accounted for)pic.twitter.com/B59QOTtCar
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The electric field in electrodynamics (in contradistinction with electrostatics) is not the gradient of a scalar potential. Also the potential itself is not a gauge invariant entity. So I think 'equipotential lines' don't have a physical significance. Am I missing something ? 1/2
well the scalar potential of a relativistically moving charge is indeed a well defined potential, this is how i colored the contour plot. However, they are only equipotentials if E = -grad(φ), which is generally not true in elec. dynamics https://en.wikipedia.org/wiki/Li%C3%A9nard%E2%80%93Wiechert_potential …
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so perhaps i was a bit sloppy with my terminology, however, they do correspond to lines of equal φ although that isn't technically a potential
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Thanks for replying. But I humbly disagree. The Wikipedia calculation is in a certain choice of gauge i.e. Lorenz gauge. A different choice of gauge would yield a different $\phi$. E.g. $\phi=0$ in Coulomb gauge. In fact, $\phi$ can be chosen to be any function of spacetime ..1/n
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