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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. Anomaly Canceller‏ @litgenstein 15 Oct 2019
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      Replying to @MattersDarkly

      Wow that’s a really good question, I don’t see any prima facie reason why you couldn’t finesse a linear theory

      2 replies 0 retweets 1 like
    2. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @litgenstein @MattersDarkly

      what do you mean by a 'linear group'?

      3 replies 0 retweets 1 like
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @InertialObservr @litgenstein @MattersDarkly

      i feel like i'm being messed with >:0

      0 replies 0 retweets 0 likes
    4. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @MattersDarkly @litgenstein

      well you said non-linear group lmao

      1 reply 0 retweets 0 likes
    5. Joe Bebel, PhD‏ @joeintheory 15 Oct 2019
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      Replying to @InertialObservr @MattersDarkly @litgenstein

      It doesn’t help that SU(n) is a group of unitary matrices which is hard to not be linear (at least in one sense)

      1 reply 0 retweets 0 likes
    6. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @joeintheory @MattersDarkly @litgenstein

      i mean .. the matrix group is by definition a linear representation ..

      1 reply 0 retweets 0 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @InertialObservr @joeintheory and

      that's exactly what i'm saying haha .. SU(N) is a linear representation .. so hard to tell what he meant is all

      1 reply 0 retweets 0 likes
    8. Joe Bebel, PhD‏ @joeintheory 15 Oct 2019
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      Replying to @InertialObservr @MattersDarkly @litgenstein

      I think linear here means there is a one to one map to a matrix group. Not every infinite group has this, eg real addition and SU(n), I think? (Im not totally sure?)

      2 replies 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @joeintheory @MattersDarkly @litgenstein

      hmm .. don't think that's what he's referring to

      10:20 PM - 15 Oct 2019
      0 replies 0 retweets 0 likes
        1. New conversation
        1. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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          Replying to @MattersDarkly @joeintheory @litgenstein

          I agree if that's the case .. but this is just the first time i've ever heard the assertion that they don't satisfy superposition

          0 replies 0 retweets 0 likes
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