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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. Anomaly Canceller‏ @litgenstein 15 Oct 2019
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      Anomaly Canceller Retweeted 〈 Berger | Dillon 〉

      Quiz: why is this the case? QM and electromagnetism share it!https://twitter.com/InertialObservr/status/1184161563113967616 …

      Anomaly Canceller added,

      〈 Berger | Dillon 〉 @InertialObservr
      Electric fields, being vector fields, satisfy the "Superposition Principle" That is, the result of adding two E-fields is another E-field given by the vector sum of the two individual fields at each point in space pic.twitter.com/0LexMmGQR2
      7 replies 1 retweet 17 likes
    2. Anomaly Canceller‏ @litgenstein 15 Oct 2019
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      Replying to @MattersDarkly

      Wow that’s a really good question, I don’t see any prima facie reason why you couldn’t finesse a linear theory

      2 replies 0 retweets 1 like
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @litgenstein @MattersDarkly

      what do you mean by a 'linear group'?

      3 replies 0 retweets 1 like
    4. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @InertialObservr @litgenstein @MattersDarkly

      i feel like i'm being messed with >:0

      0 replies 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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      Replying to @MattersDarkly @litgenstein

      well you said non-linear group lmao

      10:10 PM - 15 Oct 2019
      1 reply 0 retweets 0 likes
        1. New conversation
        1. Joe Bebel, PhD‏ @joeintheory 15 Oct 2019
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          Replying to @InertialObservr @MattersDarkly @litgenstein

          It doesn’t help that SU(n) is a group of unitary matrices which is hard to not be linear (at least in one sense)

          1 reply 0 retweets 0 likes
        2. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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          Replying to @joeintheory @MattersDarkly @litgenstein

          i mean .. the matrix group is by definition a linear representation ..

          1 reply 0 retweets 0 likes
        3. 11 more replies
        2. New conversation
        1. 〈 Berger | Dillon 〉‏ @InertialObservr 15 Oct 2019
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          Replying to @MattersDarkly @litgenstein

          i'm confused .. the gauge fields are vector fields at least infinitesimally what's nonlinear about Aμ + Bμ?

          0 replies 0 retweets 0 likes
        2. 2 more replies

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