Let S(x) denote the number of trials until the sum exceeds x. In this case we want S(1). Suppose the first trial equals f < x, then: S(x) = 1 + integral of S(x - f) between 0 and x => dS(x)/dx = S(x) and we know that S(0) = 1 Hence, S(x) = e^x and S(1) = e
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we need
@jack to fix this
IIRC there's a bot that likes tweets every time you capitalize LateX incorrectly .. now we wait ..
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YES!
@AndrewM_Webb will get a kick outta thisThanks. Twitter will use this to make your timeline better. UndoUndo
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