taking derivatives componentwise and also it’s an invariant tensor of SU(N)
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I'm pretty sure the epsilon tensor is only an invariant of SU(N) not SL(N) .. The δ_{i \bar{j}} is an SL(N) invariant
Because there are two invaraint tensors of SU(N), and i know the delta is inherited and they can't have the groups can't have the same invariant tensors i thought
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The delta comes from the unitary part, not the special part. The epsilon comes from the special part. See my previous comment.
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yea you're right .. guess it's getting a bit late for me
End of conversation
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