You should raise the indices of the contravariant components a_j, b_j, otherwise this does not make sense in terms of Einstein summation.
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Replying to @ValFadeev
In Euclidean space they’re equal since the metric is kronecker
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Replying to @InertialObservr @ValFadeev
It's not only about non-euclidean metric; lower/upper indices are about co/contra-variance.
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Replying to @lisyarus @ValFadeev
Okay fair but they transform identically when the metric is identity
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The real reason I didn’t do it is because I didn’t want to freak ppl out who haven’t seen it before tbh.. am I lying? Just a bit.. but lying is good for pedagogy lol
1:00 AM - 18 Sep 2019
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