You should raise the indices of the contravariant components a_j, b_j, otherwise this does not make sense in terms of Einstein summation.
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Replying to @ValFadeev
In Euclidean space they’re equal since the metric is kronecker
2 replies 1 retweet 11 likes
Replying to @InertialObservr @ValFadeev
Also here the equation makes zero sense if there’s no summation implied, though I should clarify
12:55 AM - 18 Sep 2019
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