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Replying to @PhitauSanitere
yea i found it when i was looking through G&R lol
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Replying to @aminorex
come onnn i know you can just google big russian book of integrals and it'll come up
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Replying to @InertialObservr @aminorex
I did that and when I 'll have time I'll print it, it's better on paper (or buy it ...) but you know there so many intersting mathematics (btw I found some proof of the hint,wth telescopic quotient starting from 1/(1-x)=1/(1-x^2)x(1+x)...1/(1-x^(2^k))=1/(1-x^(2k+1))x(1+x^(2k))
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multiply the inequalities... and take the limit for |x|<1 not too hard in fact
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but now I think I should take some sleep... Have a good night !
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