√2 raised to itself infinitely many times is 2pic.twitter.com/0l9dhhs3GV
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Yeah, I’m 99% sure this only works for sqrt(2) and the trivial case. I can’t figure out how to prove it though.
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let’s see
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Your goal is to solve x^y = y so I suppose you can have y=n, x = n^(1/n).
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