-
-
-
This is an invalid proof because it assumes the tower converges and has a solution for all values of k, e.g, Let k=4 => k^(1/k) = √2 => √2^√2^√2^... ∞ = 4 But √2^√2^√2^... ∞ = 2 Paradox
- 1 more reply
New conversation -
-
-
And other than 1, the only number this works for, right?
-
Seems that way. Here's lim of x^x^x^... and x^2 in range 0.5 to 1.5, and it looks like the lim of x^x^... converges to a finite value if 0 <= x < e^(1/e), and diverges if x > e^(1/e)pic.twitter.com/6UcEMJtBZW
- 14 more replies
New conversation -
-
-
You're wrong. The tetration converges when x ∈ [e^(-e), e^(1/𝑒)].
- 6 more replies
New conversation -
-
WHY WOULD IT WANT TO DO THAT
-
It gets bored
- 1 more reply
New conversation -
-
-
Yeah, I’m 99% sure this only works for sqrt(2) and the trivial case. I can’t figure out how to prove it though.
-
the proof is pretty straight forward i think
- 4 more replies
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.