The "notational second derivative" is true only when the function 𝑓(𝑥) is of a very specific form 
pic.twitter.com/ZFTgHFcqxp
-
But you need something to "turn off" the 'x' dependence, right? Like what choices of parameters give f(x)=2? I think just moving the constant to be in front of the x would fix it(?)
what i'm saying is that the full solution is y(x) = c -ln(x+b) and i just wrote c--> ln(c) for compactness
-
-
Yeh but f(x)=2 is also a solution but not covered by this, right?
-
absolutely it is.. this is the most general solution to the 2nd order ode, and you can certainly find initial conditions to make it a "particular" solution, which is what you're asking for..
- 7 more replies
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.