Or a constant function :)
The "notational second derivative" is true only when the function 𝑓(𝑥) is of a very specific form 
pic.twitter.com/ZFTgHFcqxp
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that's what the ln(c) is in there for ;)
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The way to solve it is shown (picture might be see-through?)pic.twitter.com/WTy0cR23pq
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i have no idea why you do all that on your phone lol
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"Notational" second derivative? I've never heard this before
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that's cause i made the term up lmao
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You accept it they are not equal... oh my god we have a “non-caveman” physicist
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a little bit of operator theory just to piss you offpic.twitter.com/GdiDmxKFrQ
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If you cancel everything you get f^2 = df lolololol But f^2 = 0 if f is a scalar differential form, so we just have df = 0. If we are on a contractable space the solution for this is f = dg with arbitrary g. Enough shitposting for today, good night.
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What about if 2=n?... and if n=1/2? Only for n=1 it is true in general, provided that the function is differentiable. Try to work out if 2 Is replaced by 3.
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