Where does the Coulomb interaction comes from?
-
If one says U = e^2/r, one thinks on 1) a given position 2) a localized charge. which is usually not always the case the case in QM, not even in a bound state like an atom.
but all of that is covered from the fact that its wave function must obey the wave equation.. if you ask where the particle is you have to integrate it against the probability distribution defined by the schrodinger wave equation, where the coordinates are treated as random vars
-
-
Of course, but one could say that that is a posteriori.
-
i'm not sure what you mean.. the coordinates are treated as random variables of a distribution that need to be integrated over for meaningful results.. this isn't just physics.. just because a distribution f(x,y) has coordinates x,y doesn't mean x,y definitely happen
- 4 more replies
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.