If you drop an object through a hole in the Earth stretching from the North Pole to the South Pole, it would oscillate back and forth about 17 times per daypic.twitter.com/crCfBFK2qp
Show this thread
-
Assumptions: •No air resistance •Earth is a perfect sphere w/ uniform mass density •Such a hole doesn't collapse under gravity
Show this thread
Another neat fact is that the falling object and a satellite orbiting just above the Earth's surface will have the exact same oscillation period!pic.twitter.com/g7fgYSlmM6
-
-
I thought gauss law would imply no gravity at all... very étrange i have ro think that again
-
let me rephrase, there's only zero gravity at the center of the earth. at every other point along the line there is a nonzero field
- 1 more reply
New conversation -
-
-
Period (or frequency) is independent of latitude, so the latitudes are not required to be the same for both at every given time (but must be the same at some times), but your graphic appears to suggest that with the correct initial conditions they can be. Is that correct?
-
yes, i've used initial conditions where they are
- 1 more reply
New conversation -
-
-
I just fucking threw up. This is beautiful.
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
Thanks vector addition!
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
that’s neat!
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
which proves that orbiting is just falling with style
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
But it goes half pi times as fast!
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
and for any cord? (assuming it slides frictionlessly)
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.