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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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    This is definitely one of the coolest things I think I've ever figured out.. 🔹For some reason, i decided to take the geometric sum (S₁) of a geometric series (S) 🔹Then i decided to take the sum of *that* geometric series (S₂) . . Then a familiar pattern started to emerge...pic.twitter.com/CxFxPWJw8O

    5:19 PM - 4 Jul 2019
    • 36 Retweets
    • 212 Likes
    • Collins Vergil Bradley Vigil Abraham Velasco R. (אברהם) Do you reckon? TM85 Y.J. Danjuma, Ph.D Wankar FC m_nt_rpt rsn
    8 replies 36 retweets 212 likes
      1. New conversation
      2. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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        I found then that if you iterate a geometric series on itself and then take the number of iterations to infinity you obtain... φ-1 😀 pretty neat..pic.twitter.com/dgtFoPFOBE

        6 replies 10 retweets 80 likes
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      3. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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        Continued fraction of the Golden Ratio φpic.twitter.com/TX1jBiuCOd

        2 replies 8 retweets 80 likes
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      4. End of conversation
      1. New conversation
      2. Silent Cal‏ @KralcTrebor 4 Jul 2019
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        Replying to @InertialObservr

        I think this is geometrically the fact that there is only one spiral that does like the perfect spiralling down to a point. <waves hands>

        1 reply 0 retweets 2 likes
      3. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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        Replying to @KralcTrebor

        What do you mean exactly? There’s many many spirals

        2 replies 0 retweets 0 likes
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      2. Chris Moorhead‏ @sprscnnctns 5 Jul 2019
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        Replying to @InertialObservr

        You can write the recurrence relation. At the limit the n+1 term is the same as the nth term and you have the quadratic that solves to give the golden ratio. Also rewriting Sn as a/b you get Sn+1=b/(a+b) which can describe the ratios between successive Fibonacci sequence terms

        1 reply 0 retweets 2 likes
      3. Chris Moorhead‏ @sprscnnctns 5 Jul 2019
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        Replying to @sprscnnctns @InertialObservr

        I should say Fibonacci like sequence. The main thing is the recurrence relation. Nice observation though. :)

        1 reply 0 retweets 2 likes
      4. 1 more reply
      1. Pascal Kwanten‏ @pascalkwanten 4 Jul 2019
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        Replying to @InertialObservr

        Nice these continued fractions analysis.

        0 replies 0 retweets 2 likes
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      1. ΡΗΚΚ‏ @Ron_castillo 5 Jul 2019
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        Replying to @InertialObservr

        Please, give me a case where |r|<1=>|S|<1

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      1. wtr1st‏ @wtresearch1 5 Jul 2019
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        Replying to @InertialObservr

        one of those results where your mouth stays open for a while

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      1. Ranjan Singh‏ @ranjanpsingh2 5 Jul 2019
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        Replying to @InertialObservr

        Why the minus sign?

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