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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. Pascal Kwanten‏ @pascalkwanten 3 Jul 2019
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      Replying to @InertialObservr

      f(x)=(f(-x))^1, substitute x→-x and +/-a → -/+a yielding:pic.twitter.com/BxWd9YCDD2

      2 replies 2 retweets 9 likes
    2. Pascal Kwanten‏ @pascalkwanten 3 Jul 2019
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      Replying to @pascalkwanten @InertialObservr

      While taking a shower I realized that the problem also can be solved by solving the functional eqn. for f(x): f(x)f(-x)=1 Take x=0 therefore (f(0))^2=1 so: f(0)=+/-1 but f(0)=/=-1 since 1+f(x)=/=1 (not equal to 1). So f(0)=1, implying f(x)=1 so 1/(1+f(x))=1(1+1)=1/2 yielding "a"

      1 reply 0 retweets 3 likes
    3. Pascal Kwanten‏ @pascalkwanten 3 Jul 2019
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      Replying to @pascalkwanten @InertialObservr

      The same approach was used by Einstein in his derivation of the Lorentz transformations with phi(v)phi(-v)=1, yielding phi(v)=1.pic.twitter.com/bFwUoY6jS0

      1 reply 2 retweets 6 likes
    4. Pascal Kwanten‏ @pascalkwanten 3 Jul 2019
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      Replying to @pascalkwanten @InertialObservr

      Reminds me to: UU^+=UU^(-1)=1, where U is a unitary matrix, so also: f(x)=exp(ix) and f(-x)=exp(-ix)=(exp(ix))^(-1) (is a solution), have to check ;-)

      2 replies 0 retweets 1 like
    5. Pascal Kwanten‏ @pascalkwanten 3 Jul 2019
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      Replying to @pascalkwanten @InertialObservr

      In general: f(x)=p^x is a solution. (Where p real or complex) and f=/=-1

      1 reply 0 retweets 0 likes
    6. Pascal Kwanten‏ @pascalkwanten 4 Jul 2019
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      Replying to @pascalkwanten @InertialObservr

      In general f(x)=p^x is a soln and therefore also f(x)=e^x=exp(x):pic.twitter.com/Mo403ImnyH

      1 reply 0 retweets 1 like
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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      Replying to @pascalkwanten

      if you TeX'd your tweets i probably would have RTd you 50 times by now

      2 replies 0 retweets 1 like
    8. Pascal Kwanten‏ @pascalkwanten 4 Jul 2019
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      Replying to @InertialObservr

      Forgotten all about LaTeX that'S more than 25 years ago ;-) Getting too lazy as manager and entrepreneur ;-)

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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      Replying to @pascalkwanten

      if you can remember all that HEP, you can remember TeX;)

      11:09 AM - 4 Jul 2019
      • 1 Like
      • Pascal Kwanten
      2 replies 0 retweets 1 like
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        1. Pascal Kwanten‏ @pascalkwanten 4 Jul 2019
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          Replying to @InertialObservr

          I remember Microsoft Word/Office. (Worked for more than 5 years for Microsoft), LaTex or TeX too confusing and user unfriendly but the nonwysiwig editor TeX has beautiful output ;-) *.tex; *.dvi and , *.ps postscript files compiled ;-)

          1 reply 0 retweets 3 likes
        2. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jul 2019
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          Replying to @pascalkwanten

          you studied Theoretical Particle Physics under Gerard `t Hooft, and you're trying to tell me that TeX is too complicated?!?!

          1 reply 0 retweets 2 likes
        3. 2 more replies
        1. Pascal Kwanten‏ @pascalkwanten 4 Jul 2019
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          Replying to @InertialObservr

          Actually: X=Chi ;-) to make it even more complicated ;-)

          0 replies 0 retweets 0 likes
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