In fact, the general form isn't difficult to prove at all.. Try it yourself!pic.twitter.com/PcV24x4B71
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came up with this cute lil guy in the comments of a previous thread.. Thought it deserved its own tweetpic.twitter.com/tCL4x65MxY
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hmmm interesting.... (\sum_{k=1}^n k )^2 = \sum_{k=1}^n k^3
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tbh this is one of my faves i mean look at the lil guy
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(Let's have it) "continuous(ly)" (about) Nicomachus.
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Also valid on an arbitrary interval [a,b] (and not only on [0,1]), with: a and b (e.g.) real (these can also be complex). Similar for the other integral.
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