0
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the function isn’t odd under x->-x
It would be odd under x+1 —> -(x+1), but then the integral is shifted by one unit and hence you lose the symmetry that makes the integral 0
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the function isn’t odd under x->-x
It would be odd under x+1 —> -(x+1), but then the integral is shifted by one unit and hence you lose the symmetry that makes the integral 0
