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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 24 Jun 2019
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      In Non-Standard Calculus the notion of an 𝒊𝒏𝒇𝒊𝒏𝒊𝒕𝒆𝒔𝒊𝒎𝒂𝒍 is formalized 👉One such formalization is the extension of ℝ → *ℝ 👉*ℝ is called the hyperreals 👉In *ℝ an infinitesimal d𝑥 is a number that is greater than zero, but smaller than any other real numberpic.twitter.com/m6c1462ccf

      9 replies 19 retweets 92 likes
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    2. Eddy Bruel‏ @ejpbruel 24 Jun 2019
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      Replying to @InertialObservr

      How does this work exactly, since you can pick a real number to be as close to zero as you want?

      3 replies 0 retweets 1 like
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 24 Jun 2019
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      Replying to @ejpbruel

      Informally, you can think of this as saying "no you actually get as close as you want. The closest you can get is infinitesimally close" That is there is a "smallest" number that is nonzero in the hyperreals

      1 reply 0 retweets 0 likes
    4. Eddy Bruel‏ @ejpbruel 24 Jun 2019
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      Replying to @InertialObservr

      Does this imply that hyperreals don't have the property that given two hyperreals a and b, I can always find a hyperreal c such that a < c < b?

      1 reply 0 retweets 0 likes
    5. 〈 Berger | Dillon 〉‏ @InertialObservr 24 Jun 2019
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      Replying to @ejpbruel

      If a,b,c are all infinitesimals I believe that is correct. However, through something called the transfer principle all "regular" notions of the reals gets carried over, except those having to do with sets of numbers

      1 reply 0 retweets 0 likes
    6. Eddy Bruel‏ @ejpbruel 24 Jun 2019
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      Replying to @InertialObservr

      I mean, if it werent correct then there would exist a hyperreal number x such that 0 < x < dx.

      1 reply 0 retweets 0 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 24 Jun 2019
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      Replying to @ejpbruel

      My understanding is that the hyperreals are non-Archimedian, and so I'm trying to tread softly with the infinitesimals, but I think that's correct

      2 replies 0 retweets 1 like
    8. Eddy Bruel‏ @ejpbruel 24 Jun 2019
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      Replying to @InertialObservr

      Heh. I'm going to have to look up Archimedian. I don't have a math background, but I am very interested in this stuff, so your tweets on the subject are appreciated! :-)

      1 reply 0 retweets 1 like
    9. Eric Lengyel‏ @EricLengyel 24 Jun 2019
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      Replying to @ejpbruel @InertialObservr

      There is neither a smallest positive real number nor a greatest positive infinitesimal, but all infinitesimals are less than all positive reals. And yes, by the transfer principle, for any hyperreals a and b, finite or otherwise, with a < b, there exists c such that a < c < b.

      1 reply 0 retweets 1 like
      〈 Berger | Dillon 〉‏ @InertialObservr 24 Jun 2019
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      Replying to @EricLengyel @ejpbruel

      thanks for clearing that up!

      1:27 PM - 24 Jun 2019
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      • Eric Lengyel
      0 replies 0 retweets 1 like

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