Why does white light entering a prism leave a rainbow?
When light hits the prism at an angle θ₀, the exiting angle is given by sinθ = sinθ₀ /𝑛
Different colors have different 𝑛 (in glass)
So each color will exit the prism with a slightly different angle θpic.twitter.com/yIsrbkk76p
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Replying to @InertialObservr
But ELI5 why different colors/frequencies have different n’s?

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Replying to @johnnygreavu
Depending on what level of description you're looking for it's rather nontrivial. But you you can think of it as the atoms of the glass have particular "resonant" frequencies.. Being made of charged particles, they will interact with the light in slightly different ways
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Replying to @InertialObservr
That’s probably the best particle interpretation. To me it seems cleanest to think in terms of waves here though.
Boundary conditions require wave to be continuous at boundary, and since wave velocity changes upon entering medium, wavelength must change?
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Replying to @johnnygreavu
These are all consistent, but I prefer to think about them more fundamentally
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Replying to @InertialObservr
But it doesn’t really make sense to discuss a single bare photon in a material. It reduces system to a vacuum. And, diamond (~2.4) and ash (~1.1) are both just carbon but have greatly different n’s. The index of refraction depends equally on the geometry as it does atom type.
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Replying to @johnnygreavu
Well, I would use the term "fundamental" in terms of "building blocks"
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Replying to @InertialObservr
Isn’t it excitations in fields (waves) which give rise to particles?
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Heuristically yes, but those are fundamental fields permeating all spacetime, not macroscopic wave that arise from a coherence effect
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