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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 2 Jun 2019
      • Report Tweet
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      This equality holds for *all* real numbers N,M 👀 Can you see why?pic.twitter.com/LvR2r0y6iT

      28 replies 244 retweets 800 likes
      Show this thread
    2. Valentin Fadeev‏ @ValFadeev 2 Jun 2019
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      Replying to @InertialObservr

      One-trick pony strikes againpic.twitter.com/eDIXe5w6Pz

      4 replies 5 retweets 83 likes
    3. Miller Mrosek‏ @MillerTimeSport 7 Jun 2019
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      Replying to @ValFadeev @InertialObservr

      Can you please show how you go from 4th to 5th line? (Specifically how you get I)

      1 reply 0 retweets 0 likes
    4. 〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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      Replying to @MillerTimeSport @ValFadeev

      split up the integral over the numerator, and then look at the very first tweet. The original integral is equal to I

      1 reply 0 retweets 0 likes
    5. Miller Mrosek‏ @MillerTimeSport 7 Jun 2019
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      Replying to @InertialObservr @ValFadeev

      Makes sense. In the 2nd line the bounds (inf --> 0 rather than 0 --> inf) threw me off. Any significance to that?

      1 reply 0 retweets 0 likes
    6. 〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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      Replying to @MillerTimeSport @ValFadeev

      You get a minus sign from the u sub you can use to flip the blinds

      2 replies 0 retweets 0 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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      Replying to @InertialObservr @MillerTimeSport @ValFadeev

      bounds*

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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      Replying to @InertialObservr @MillerTimeSport @ValFadeev

      I’m not entirely sure what you’re asking, but I’m near certain there’s no typo

      8:49 PM - 7 Jun 2019
      1 reply 0 retweets 0 likes
        1. New conversation
        1. Miller Mrosek‏ @MillerTimeSport 7 Jun 2019
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          Replying to @InertialObservr @ValFadeev

          Why would inf be the lower bound when 0 is the top bound? (3rd line)

          1 reply 0 retweets 0 likes
        2. 〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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          Replying to @MillerTimeSport @ValFadeev

          Take u=1/x, then the bounds go form u(0) ->u(inf) = inf -> 0.. since there is a minus sign from du we can absorb the negative and flip the bounds as to return the original 0->inf

          1 reply 0 retweets 0 likes
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