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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 6 Jun 2019
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      Suppose you're a little creature living on a Möbius strip. 👉Then after "walking in a circle" (i.e. 2π radians), you will actually be upside-down. 👉In order to get back to where you started, you have to go around twice! Check out my neat gif! 👇pic.twitter.com/1MMvp83IWG

      6 replies 21 retweets 111 likes
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      〈 Berger | Dillon 〉‏ @InertialObservr 6 Jun 2019
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      The 𝐏𝐚𝐮𝐥𝐢 𝐈𝐝𝐞𝐧𝐭𝐢𝐭𝐲 tells us how to rotate a 2 component 𝒗𝒆𝒄𝒕𝒐𝒓 of complex numbers, called a "spinor", around an axis θ̂. 👉for spinors, a rotation by 2π yields -1 👉only a rotation by 4π yields identity ..sound familiar?pic.twitter.com/ECGtLshlH2

      2:52 PM - 6 Jun 2019
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      • 21st Century FDR Lucho chaos harmonique Pascal Kwanten Dave Langdon Schrodinger's Cat Derek Orr emilio lindosa lucas Crypto. 𝕵eon Nam₿i
      13 replies 16 retweets 61 likes
        1. 〈 Berger | Dillon 〉‏ @InertialObservr 7 Jun 2019
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          An object that existed in a Möbius-strip-shaped universe would be indistinguishable from its own mirror image 👉 This crab's larger claw switches between left to right with every circulation (GIF not mine)pic.twitter.com/n3JHJdy0jJ

          2 replies 2 retweets 18 likes
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        2. EXTREM :II: TOPOLOGIE FAN‏ @zimtyzimtbart 14 Jul 2019
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          Replying to @InertialObservr

          Fun fact: Spinor calculus already contains tensor calculus. Every tensor has a spinor analogue. A spin-vector multiplied by its complex conjugate produces a null vector.

          1 reply 0 retweets 0 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 14 Jul 2019
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          Replying to @zimtyzimtbart

          by null vector you mean SU(N) invariant? Then i agree. What's more is that you can construct all tensor reps of SU(N) by suitable direct products of the fundamental representation!

          1 reply 0 retweets 1 like
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        2. Joshua Silva‏ @silvascientist 6 Jun 2019
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          Replying to @InertialObservr

          I don’t get what this formula is saying... it’s not returning the complex vector that you get from rotating, it’s giving some scalar whose relation to the rotation is not at all clear. Can you elaborate?

          1 reply 0 retweets 0 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 6 Jun 2019
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          Replying to @silvascientist

          It's a 2x2 matrix that acts on a 2 component complex vector (i.e. a spinor).

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        2. David Quintero‏ @davidsuculum 6 Jun 2019
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          Replying to @InertialObservr

          Besides the Euler identity, it seems to me quite related to the rotation using quaternions.

          1 reply 1 retweet 3 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 6 Jun 2019
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          Replying to @davidsuculum

          it's exactly that!

          1 reply 1 retweet 1 like
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        1. Pascal Kwanten‏ @pascalkwanten 9 Jun 2019
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          Replying to @InertialObservr

          Quaternions are in fact equivalent (i.e. can de represented by) to Pauli matrices that transform (complex) vector components into 2-component spinor components via: In that sense quaternions can be spinors.pic.twitter.com/iw2rqF8rrg

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        2. Sami‏ @saminakouzi 6 Jun 2019
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          Replying to @InertialObservr

          I think i saw something similar in hilbert space while studying quantum mechanics. Somehow to get back where i am i rad to rotate by 4π rad ( assuming i started at |+z> and wanted to get back to |+z>) rotating by 2π rad got me to |-z>. I was creeped out

          2 replies 0 retweets 3 likes
        3. Valentin Fadeev‏ @ValFadeev 6 Jun 2019
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          Replying to @saminakouzi @InertialObservr

          This is what happens on the Bloch's sphere where the "north" and "south" poles correspond to orthogonal states.

          0 replies 0 retweets 2 likes
        4. End of conversation

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