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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 20 Mar 2019
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      This is Real.pic.twitter.com/E5JQYz39dp

      23 replies 117 retweets 444 likes
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      〈 Berger | Dillon 〉‏ @InertialObservr 4 Jun 2019
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      The 𝑖ᵗʰ root of 𝑖 is realpic.twitter.com/9ydxEkQ5W8

      11:17 AM - 4 Jun 2019
      • 16 Retweets
      • 150 Likes
      • taylor. Adam Nash #StayAtHaym Santiago Itzcoatl 🗿 Sahil Singla StatCafe wat a disaster Pedro MoralesAlmazan
      8 replies 16 retweets 150 likes
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        2. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jun 2019
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          Note though, when taking powers of complex numbers we have to be careful. Technically, if we don't restrict the range of θ to be [0,2π) then i^i takes on infinitely many values. All of which, however, are real.

          6 replies 4 retweets 57 likes
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        3. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jun 2019
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          Proof that 𝑖ⁱ is real and equal to exp(-π/2). (Note: we are working in the principal branch of eⁱˣ)pic.twitter.com/OUo4TSJCDk

          4 replies 14 retweets 69 likes
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        4. End of conversation
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        2. eylem gercek boss‏ @_eylem_99 29 Jul 2019
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          Replying to @InertialObservr

          Hmmmm 🤔 Not quite sure about that radical being used with imaginaries 🤷‍♂️

          1 reply 0 retweets 0 likes
        3. إبراهيم العليان‏ @ialolyan 29 Jul 2019
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          Replying to @_eylem_99 @InertialObservr

          I agree.

          1 reply 0 retweets 2 likes
        4. 10 more replies
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        2. josue duval‏ @duval_josue 4 Jun 2019
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          Replying to @InertialObservr

          Is it true?

          2 replies 0 retweets 1 like
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 4 Jun 2019
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          Replying to @duval_josue

          yup! in the principal branch!

          0 replies 0 retweets 1 like
        4. End of conversation
        1. New conversation
        2. SIRISYS‏ @SIRISYSPrime 29 Jul 2019
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          Replying to @InertialObservr

          SIRISYS Retweeted Elon Musk

          https://twitter.com/elonmusk/status/1129100691367124993 …

          SIRISYS added,

          Elon MuskVerified account @elonmusk
          Replying to @elonmusk @engineers_feed
          Set of all math jokes that are actually funny is pretty small (sigh)
          1 reply 0 retweets 2 likes
        3. 〈 Berger | Dillon 〉‏ @InertialObservr 29 Jul 2019
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          Replying to @SIRISYSPrime

          obviously @elonmusk needs to follow me, then

          1 reply 0 retweets 1 like
        4. 18 more replies
        1. Fahmi Riyaz‏ @fahmi_riyaz 4 Jun 2019
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          Replying to @InertialObservr

          z=cos 90 +i sin 90 =i, so theta is 90 Now, writing in z=r e ^ i {theta} form, z=e ^i(pie/2) {r=1 since sin^90+cos ^90=1} Now, i ^ (1/i)= e ^{i(pie/2)}*1/i =e^(pie/2), hence proved 🤔

          0 replies 0 retweets 1 like
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        1. bob‏ @huntthesnark 29 Jul 2019
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          Replying to @InertialObservr

          Ah, brings back memories. Caught the attention of a math prof in the first class meeting by answering this one in a couple seconds while everyone else in class looked at me like I'd grown an extra head.

          0 replies 0 retweets 1 like
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